# Rearranging a 512x64 matrix into a 32x1024 matrix

조회 수: 1(최근 30일)
Shanice Kelly 12 Jan 2021
편집: Bruno Luong 13 Jan 2021
I have a 512x64 matrix imported from a excel file. I need to turn it into a 32 x1024 matrix by keeping row 1 column 1 and row 1 column 2 elements in their position and moving all other columns in row 1, and also moving the elements of the other 511 rows.
so row 1 column 3 moves to row 2 column 1
row 1 column 4 moves to row 2 column 2
row 1 column 5 moves to row 3 column 1
row 1 cloumn 6 moves to row 3 column 2
etc... so row 1 transforrms from 1x64 to 32x2
Then move to rearranging row 2
row 2 column 1 moves to row 1 column 3
row 2 column 2 moves to row 1 column 4
I would like to do this for all 512 row until I have a 32 x1024 matrix. I really hope I explained that well enough. I really do not want to have to do this manually in excel so thank you in advance for any help.

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### 채택된 답변

Bruno Luong 13 Jan 2021
편집: Bruno Luong 13 Jan 2021
% Assuming A is your input matrix of size 512 x 64
% such as
% A=reshape(1:512*64,64,512)';
B = reshape(permute(reshape(A,[512 2 32]),[3 2 1]),[32 1024]);

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### 추가 답변(1개)

Matt J 12 Jan 2021
편집: Matt J 12 Jan 2021
##### 댓글 수: 2표시숨기기 이전 댓글 수: 1
Matt J 13 Jan 2021
The order is not arbitrary. It extracts data from the initial matrix column-by-bolumn and fills the new matrix column-by-column, e.g.,
A = (1:8).'
A = 8×1
1 2 3 4 5 6 7 8
B = reshape(A,[2,4])
B = 2×4
1 3 5 7 2 4 6 8

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R2020a

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