Averaging the selected vector ranges

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Lev Mihailov
Lev Mihailov 2020년 11월 6일
댓글: Mathieu NOE 2020년 11월 9일
Hello! I need to average the values ​​of a vector over 25 values
fr = mean(reshape(VectorTime, 25, [])); %
Error using reshape
Product of known dimensions, 25, not divisible into total number of elements, 523.
Error in TimeAndWordNN (line 1234)
frr = mean(reshape(VectorTime, 25, []));
When I try to make such a variant, I get an error, please help
for i=1:25:length(VectorTime) && i<length(VectorTime)
frr=mean(VectorTime(i:i+1)) % i(1)=1 i(2)=26
end
% tried what i need to do through the loop but nothing worked

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Mathieu NOE
Mathieu NOE 2020년 11월 6일
hello
my 2 fold suggestion , first is new code according to your expected results , and second is based on sliding averaging - function is in attachement !
enjoy
samples = 1000;
VectorTime = 1 + sin(2*pi*(1:samples)/samples)+ 0.25*rand(1,samples);
buffer = 25; % nb of samples for averaging
% zero overlap mean averaging
for ci=1:floor(length(VectorTime)/ buffer)
start_index = 1+(ci-1)*buffer;
stop_index = min(start_index+ buffer,length(VectorTime));
time_index(ci) = round((start_index+stop_index)/2);
frr(ci) =mean(VectorTime(start_index:stop_index)) %
end
figure(1),
plot((1:samples),VectorTime,'b',time_index,frr,'or');
% sliding avg method
out = myslidingavg(VectorTime, buffer);
figure(2),
plot((1:samples),VectorTime,'b',(1:samples),out,'r');
  댓글 수: 1
Mathieu NOE
Mathieu NOE 2020년 11월 9일
hello
please use this version of slidingavg (if you are interested in)
I have found a bug in the previous release
all the best

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