Help me to Solve ODE problem

조회 수: 1 (최근 30일)
Kevin Isakayoga
Kevin Isakayoga 2020년 9월 25일
편집: Cris LaPierre 2020년 9월 26일
Hi every one, I am trying to solve the ode function, but up until now I still couldnot figure it out why my value always NaN.
Here below is my function,
function f=model2(~,Y,ro)
rt=Y(1);
Rt=Y(2);
% Explicit equations
pw=1*0.001;
pc=3.16*0.001;
wc=pw/pc*((1/((0.5^3)*4/3*pi))-1);
T=293;
b1=1231;
C=5*10^7;
ER=5364;
yg=0.25;
yw=0.15;
RH=0.8;
cw=((RH-0.75)/0.25)^3;
v=2;
rwc3s=0.586;
rwc3a=0.172;
De293=((rwc3s*100)^2.024)*(3.2*10^-14);
kr293=(8.05*(10^-10))*((rwc3s*100+rwc3a*100)^0.975);
B293=0.3*10^-10;
alfa=1-(rt/ro)^3;
kr=kr293*exp(-ER*(1/T-1/293));
De=De293*(log(1/alfa))^1.5;
B=B293*exp(-b1*(1/T-1/293));
kd=(B/alfa^1.5)+C*(Rt-ro)^4;
L=((4*pi*(wc*(pc/pw)+1)/3)^(1/3))*ro*0.001;
Rt1=Rt/L;
z=ro/L;
if Rt1<=z
Sr=0;
elseif (Rt1>=z)&&(Rt1<0.5)
Sr=4*pi*(Rt1)^2;
elseif (0.5<=Rt1)&&(Rt1<0.5*(2^0.5))
Sr=(4*pi*(Rt1)^2)-(12*pi*(1-(0.5/(Rt1))));
elseif (Rt1>=0.5*(2^0.5)) && (Rt1<0.5*(3^0.5))
syms y x
fun = @(y,x) 8*(Rt1)/(sqrt((Rt1)^2-(x.^2)-(y.^2)));
ymin=sqrt((Rt1)^2-0.5);
xmin=@(x) sqrt((Rt1)^2-0.25-x.^2);
Sr=integral2(fun,ymin,0.5,xmin,0.5);
else
Sr=0;
end
cst=Sr/(4*pi*(Rt^2));
%Differential equations
drtdt=-((pw*cst*cw)/((yw+yg)*pc*rt^2))*1/((1/(kd*rt^2))+(((1/rt)-(1/Rt))/De)+(1/(kr*rt^2)));
dRtdt=(v-1)*(rt^2)*drtdt/Sr;
f=[drtdt;dRtdt];
end
And here is the command to run the function
clc; clear;
tspan=[0 100];
ro=4*0.001;
y0=[(ro-0.0001) (ro+0.0001)];
[t,y]=ode45(@model2,tspan,y0,[],ro);
figure (2)
plot(t,y(:,1),t,y(:,2));
legend('rt','Rt');
ylabel('mm');
xlabel('t');
axis([tspan 0 100]),grid;
Thank you for you attention! Looking forward to help my question.
Best Regard,
Kevin

채택된 답변

Cris LaPierre
Cris LaPierre 2020년 9월 26일
편집: Cris LaPierre 2020년 9월 26일
Check your equations. Sr is always zero. This causes cst to always be zero, which then causes drdt to also be zero, causing dRdt to be NaN (drdt/Sr = 0/0 = NaN).
Because the output of the first loop is the initial conditions for the next, and you are getting NaN in the first loop, your problem perpetuates. I tried tweaking the initial conditions some, but it didn't help much.
Check why Sr is always 0.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Programming에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by