storing values in a loop

조회 수: 3 (최근 30일)
Melissa
Melissa 2012년 11월 21일
I have a function of the following and it only gives the last value. I want to see a vector of Nf and pf. I tried inserting i. For example Nf(i)=Nf and received the following error:
Attempted to access Nf(2); index out of bounds because numel(Nf)=1.
Error in probabilitycounter (line 23) Nf(i)=Nf
Here is what I have written to produce actual data:
function [Nf,pf]= probabilitycounter(N,mu_x,mu_y,sig_x,sig_y)
%Starting value of Nf
Nf=0;
%Creating a loop to generate pf and Nf
for i=1:N
%Random variable declaration for ux and uy
u_x=rand(1,1);
u_y=rand(1,1);
%Normal Inverse
x=norminv(u_x,mu_x,sig_x)
y=norminv(u_y,mu_y,sig_y)
%Starting Nf and pf Calculation
if (x-y>0)
Nf=Nf+1;
else
Nf=Nf;
end
pf=Nf/N;
end
  댓글 수: 3
Melissa
Melissa 2012년 11월 21일
function [Nf,pf]= probabilitycounter(N,mu_x,mu_y,sig_x,sig_y)
%Starting value of Nf
Nf=0;
%Creating a loop to generate pf and Nf
for i=1:N
%Random variable declaration for ux and uy
u_x=rand(1,1);
u_y=rand(1,1);
%Normal Inverse
x=norminv(u_x,mu_x,sig_x)
y=norminv(u_y,mu_y,sig_y)
%Starting Nf and pf Calculation
if (x-y<0)
Nf(i)=Nf+1;
else
Nf(i)=Nf;
end
pf(i)=Nf(i)/N;
end
John Petersen
John Petersen 2012년 11월 21일
These lines look like problematic
Nf(i) = Nf+1;
Nf(i) = Nf;
Maybe you want to index the Nf on both sides?

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채택된 답변

Matt J
Matt J 2012년 11월 21일
I'm guessing this might be what you want:
function [Nf,pf]= probabilitycounter(N,mu_x,mu_y,sig_x,sig_y)
%Starting value of Nf
Nf=zeros(1,N);
%Creating a loop to generate pf and Nf
for i=2:N
%Random variable declaration for ux and uy
u_x=rand(1,1);
u_y=rand(1,1);
%Normal Inverse
x=norminv(u_x,mu_x,sig_x)
y=norminv(u_y,mu_y,sig_y)
%Starting Nf and pf Calculation
if (x-y<0)
Nf(i)=Nf(i-1)+1;
else
Nf(i)=Nf(i-1);
end
pf(i)=Nf(i)/N;
end
  댓글 수: 1
Melissa
Melissa 2012년 11월 21일
Ah so the dimensions were wrong thats why you used the zeros matrix? then had to reset the index? thank you that is exactly what I needed. I really appreciate your help :)

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