Splitting up arrays in for loops

Hi!

I am using arrays that I would like to split up based on the values in the THIRD column. For example this array:

117	299	126
130	305	126
134	299	127
131	293	127
134	299	128
129	295	128
115	296	132
121	298	132

I would like to split is up at the place where the difference between the third column values is higher than 1 (between the current value and the value underneath it). In this case I would like to end up with the following two arrays:

117	299	126
130	305	126
134	299	127
131	293	127
134	299	128
129	295	128

and

115	296	132
121	298	132

I would also like to apply this to a large dataset so not doing it manually.

I thought about using if else statements in a for loop but I don't know how to how to calculate the difference between the third column values.

Can someone help me in how to start with this?

Thank you!

Answer 1

[David Hill]

n=[0,find(diff(M(:,3))>1),size(M,1)];
for k=1:length(n)-1
    m{k}=M(n(k)+1:n(k+1),:);
end

[Ellen]

Yes I got it now, thank you!

Answer 2

[Nadya Owusu]

disp("Question 1:")%Displays question number.
a = 210;%The upper limit of the integral.
b = 0;%Lower limit of the integral.
n = 14;%Number of trapezoid sub-intervals in other words number of sections used.
h = (b-a)/n;%Length of trapezoid.
t = b:n:a;
f = (-3.19892*10.^-8)*(t.^7)+(2.77042*10.^-5)*(t.^6)+(-0.00928)*(t.^5)+(1.49974)*(t.^4)+(-1.18729*10.^2)*(t.^3)+(4.25940*10.^3)*(t.^2)+(-5.42886*10.^4)*(t)+(3.50829*10.^6);%Flow rate(t) equation. 
integral = 0;

I want to split up the data from the for loop and add it to an array. please help

for t = b:n:a 

At least one END is missing. The statement beginning here does not have a matching end.

Error in connector.internal.fevalMatlab

Error in connector.internal.fevalJSON

    array = split(f);
    disp(array)