# Conversion to char from logical is not possible.

조회 수: 55(최근 30일)
Hi,
I am trying to solve the following integral with MATLAB_R2019b.
I= @(x)((x.^(3).*exp(-x))/(x.^(3)+D(i))), ['ArrayValued';true];
L = integral(I,0,Inf);
but I get the following error:
I =
function_handle with value:
@(x)((x.^(3).*exp(-x))/(x.^(3)+D(i)))
Error using vertcat
The following error occurred converting from logical to char:
Conversion to char from logical is not possible.
Error in untitled3 (line 6)
I= @(x)((x.^(3).*exp(-x))/(x.^(3)+D(i))), ['ArrayValued';true];
Can someone help? Thank you.

#### 댓글 수: 2

Rik 29 Mar 2020
It looks like ['ArrayValued';true] is executed separately from the rest. It is also unclear to me what this code is supposed to be doing.
Ludovico Iannizzotto 29 Mar 2020
Suppose that D(i)=7.
I am trying to solve the integral from 0-inf. However, this error arises. Do you have any suggestions on how to use ['ArrayValued';true] ??
Thanks

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### 채택된 답변

Rik 29 Mar 2020
You need to pass the option as a parameter to the integral function instead of defining it earlier.
I= @(x)((x.^(3).*exp(-x))/(x.^(3)+D(i)));
L = integral(I,0,Inf, 'ArrayValued';true);

#### 댓글 수: 1

Ludovico Iannizzotto 29 Mar 2020
Thank you that was very helpful

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