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How to sort a matrix in desceding order?

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SM
SM 2020년 2월 9일
댓글: SM 2020년 2월 9일
I have a matrix such as:
A =[
0.8604 0.5134 0.9391 0.6482 0.3479 0.3308 0.7069 0.7640 0.0567 0.9052
0.9344 0.1776 0.3013 0.0252 0.4460 0.8985 0.9995 0.8182 0.5219 0.6754
0.9844 0.3986 0.2955 0.8422 0.0542 0.1182 0.2878 0.1002 0.3358 0.4685
0.8589 0.1339 0.3329 0.5590 0.1771 0.9884 0.4145 0.1781 0.1757 0.9121
0.7856 0.0309 0.4671 0.8541 0.6628 0.5400 0.4648 0.3596 0.2089 0.1040];
if i use
[~, sortOrder] = sort(A(1,:), 'descend')
then it gives
sortOrder=[3 10 1 8 7 4 2 5 6 9];
but if i apply this code for all rows such as
[~, sortOrder] = sort(A(:), 'descend')
it shows results which i dont want.
How can i solve it if i want the following outcome:
sortOrder=
[3 10 1 8 7 4 2 5 6 9
7 1 6 8 10 9 5 3 2 4
1 4 10 2 9 3 7 6 8 5
6 10 1 4 7 3 8 5 9 2
4 1 5 6 3 7 8 9 10 2];
No for loop please! I use R2017b.
Thanks in advance!

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Walter Roberson
Walter Roberson 2020년 2월 9일
[~, sortOrder] = sort(A, 2, 'descend');
  댓글 수: 1
SM
SM 2020년 2월 9일
Thank you! it works for me.

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