How can I get the first row of different matrices into one matrix?

I have a for loop stating an interval and another for loop inside that runs a backslash through intervals. The backslash produces 7 (5x1) matricies. I need to get each row into a matrix that is (7x1). Below are the first three matricies my code produced.

6.8000 (r3)

8.4500

-0.0000

6.2832

6.2832

6.1167(r3)

8.7892

-2.4183

6.5619

6.5619

4.3646(r3)

9.2953

-3.8731

6.7130

6.7130

Answer 1

[Walter Roberson]

for iteration = 1 : 7
    this_result = something \ something_else;
    combined_results(iteration,:) = this_result(1,:);
end

[Cody Cambre]

clear,clc

r1= 4.8; 
r2= 2; 
r3= 5.6011; 
r4= 9.0129;
r5= 3.1352;
r6= 3.65;
t1= -pi; 
t2=[0:2*pi];
t3= 5.59279;
t4= 5.59279; 
t5= -pi/2; 
t6= 0;

x=[ r3; r4; r5; t3; t4];

for t2=[0:2*pi];
    
    for i=1:6
   
    f1= r2.*cos(t2)-r3.*cos(t3)-r1.*cos(t1);
    f2= r2.*sin(t2)-r3.*sin(t3)-r1.*sin(t1);
    f3= r6.*cos(t6)+r5.*cos(t5)-r4.*cos(t4)-r1.*cos(t1);
    f4= r6.*sin(t6)+r5.*sin(t5)-r4.*sin(t4)-r1.*sin(t1);
    f5= t4-t3;
   
    f=[f1; f2; f3; f4; f5];
   
    A=[-cos(t3) 0 0 r3.*sin(t3) 0;
    -sin(t3) 0 0 -r3.*cos(t3) 0;
    0 -cos(t4) 0 0 r4.*sin(t4);
    0 -sin(t4) -1 0 -r4.*cos(t4);
    0 0 0 -1 1];

x= x-A\f;

r3= x(1,1);
r4= x(2,1);
r5= x(3,1);
t3= x(4,1);
t4= x(5,1);
    end
end

Heres the full code. When I put your for loop in it produced a matrix of the first answers only