How to compare contents of folders, check for missing files?

I have a folder of files, which contains .sud files and .wav files. The .wav files are decompressed .sud files and should be equal in number, however, I can see from checking the length of each of these that there is one less .wav file. It looks like one hasn't been processed and I'd like to know which one it is. How can I do this? I've put the filenames in two columns of an array and the empty cell looks like [ ].

Here is my code so far:

directory={'Y:\SoundTrap\Tawharanui\Tawharanui_5278'};

    
for j=1:length(directory)
    folder=char(directory(j));
   
    d=dir(fullfile(folder, '*.wav')); %list all .wav files in path folder
    wavfiles=length(d);                
    %wavfiles=6337
    
    e=dir(fullfile(folder, '*.sud')); %list all .sud files
    sudfiles=length(e);
    %sudfiles=6338
    
    row=1;
    
    %wavs in first column
    for i=1:wavfiles                %get filename only (remove prefix and suffix)
        disp(d(i).name);
        SN=strsplit(d(i).name,'.');
        wavfilename=SN(2);
        outputfiles(row,1)=wavfilename;
        row=row+1;
    end
    
    row=1
    
    %suds in second column
    for z=1:sudfiles
        disp(e(z).name);
        SN=strsplit(e(z).name,'.');
        sudfilename=SN(2);
        outputfiles(row,2)=sudfilename;
        row=row+1;
    end
    
end


wavfiles=outputfiles(:,1);
sudfiles=outputfiles(:,2);

Answer 1

[Walter Roberson]

[~, wav_base_names] = fileparts({d.name});
[~, sud_base_names] = fileparts({e.name});
unmatched_files = setdiff(sud_base_names, wav_base_names);