MATLAB Answers

Finding a specific rows?

조회 수: 35(최근 30일)
JamJan
JamJan 2019년 7월 18일
댓글: Adam Danz 2019년 7월 18일
I have this Matrix:
m = [0 0 0 0 0 0 0 0
0 3.410 0 0 0 0 0 0
10.83 11.87 7.240 3.470 1.610 1.610 0 0
20.99 18.23 17.72 6.010 3.790 3.790 1.100 0
25.26 20.40 22.70 7.590 6.990 6.990 1.550 0
22.86 19.13 24.48 8.280 9.240 9.240 2.180 0
14.92 15.73 23.19 8.280 11.61 11.61 2.690 0
10.83 11.87 22.18 8.280 12.79 12.79 3.010 0
9.050 10.69 22.70 8.490 14.91 14.91 3.500 0
9.840 11.19 23.75 8.490 16.02 16.02 3.790 0
9.840 11.54 24.48 8.840 16.43 16.43 4.100 0
8.070 10.20 25.18 9.180 17.73 17.73 4.750 0
5.230 8.350 24.48 9.180 19.28 19.28 5.800 0
3.680 6.630 25.18 8.840 22.49 22.49 6.980 2.190
0 3.190 22.70 7.840 28.06 28.06 8.280 3.320
0 0 13.03 6.010 34.68 34.68 10.88 5
0 0 0 3.470 32.87 32.87 13.86 5.300
0 0 0 0 15.14 15.14 12.27 0
0 0 0 0 1.240 1.240 1.450 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
40.53 25 0 0 0 0 0 0]
% * Edited by Adam Danz to allow for copy-pasting into command window
I want to find the first row where all the columns have a value below 10. How to do this? I have made an if statement, but this seems to specific and I was wondering if there would be another way.

채택된 답변

Adam Danz
Adam Danz 2019년 7월 18일
편집: Adam Danz 2019년 7월 18일
This does not require a for-loop. In fact, the last line is the solution. The first few lines just creates an example matrix where rows 3 and 13 are all below 10.
% Create a 15x7 matrix of random integers 1:20
m = randi(20,15,7);
% Rows 3 and 13 are all below 10 (maybe others, too)
m([3,13],:) = m([3,13],:)-11;
%find the first row where all the columns have a value below 10.
rowNumber = find(all(m < 10,2),1);
% find the first row AFTER ROW N where all columns are < 10
N = 3; %start at row N
rowNumber = find(all(m(N:end,:) < 10,2),1)+N-1;
  댓글 수: 7
Adam Danz
Adam Danz 2019년 7월 18일
I see. Here' how to compute N (the first non-zero row).
midx = all(m < 10,2);
N = find(midx == 0,1);
rowNumber = find(all(m(N:end,:) < 10,2),1)+N-1;

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추가 답변(1개)

Mario Chiappelli
Mario Chiappelli 2019년 7월 18일
편집: Mario Chiappelli 2019년 7월 18일
I would use a double nested For statement and a counter variable as follows:
for i = 1:31 % Number of rows
counter = 0; % Reset the counter
for j = 1:8 % Number of columns
if myMatrix(i,j) < 10
counter += 1;
end
if counter == 8 % In other words when all values are under 10
disp("Row ");
disp(i);
disp(" only contains numbers less than 10");
end
end
end
If you want it to stop after the first row is detected just add a series of break statements to break out of the for loop in the if statement that checks if the counter is equal to 8
If your matrix changes sizes over the course of the program, you are going to have to assgin the dimensions of the matrix to variables and use those as your for statement parameters.
Hope this helps :)
  댓글 수: 1
Adam Danz
Adam Danz 2019년 7월 18일
Have you tried to run this? There are several errors.
  • counter += 1; I think you mean counter = counter + 1;
  • if myMatrix(i,j) < 10 this might work for the example given but if the dimensions of myMatrix ever changes, this might break.
  • Same with i = 1:31 and j = 1:8 and counter == 8
Even after correction those errors, the algorithm doesn't work for this example matrix:
myMatrix =
0 0 0 10 10
10 10 0 0 0
0 0 0 0 0

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