How to extract column and row index and the corresponding value from a matrix?

I have a huge matrix of pixel values from an image converted into a text file. I need to convert this matrix into a table with column index, row index and the element as seperate columns of the table. How do I do this?

I'm doing this to figure out of the Centre of mass of a 2D projection of an object in the image. The image is a binary image with a single object in white and the background in black. Is there any other way to do this?

[madhan ravi]

A sample illustration would help

[Noxi]

Like this:

from -

0 1 4

7 6 0

to -

row column element

1 1 0

1 2 1

1 3 4

2 1 7

2 2 6

2 3 0

Answer 1

[madhan ravi]

m = [0  1  4
     7  6  0]; 

[Rows,Columns] = ind2sub(size(m),(1:numel(m))');
Wanted = [Rows,Columns,m(:)];
Wantedtable = sortrows(array2table(Wanted,'VariableNames',{'Rows','Columns','Elements'}),1)

[KALYAN ACHARJYA]

@Madhan I tried, could not implement it without loop. +1

Answer 2

[Andrei Bobrov]

A = [0     1     4
     7     6     0];
out = sortrows([fullfact(size(A)),A(:)]);

[KALYAN ACHARJYA]

It's great!

[Andrei Bobrov]

Thank you Kalyan!