Recursive symbolic differentiation with anonymous functions

조회 수: 3 (최근 30일)
Leo Simon
Leo Simon 2012년 8월 13일
This is closely related to an earlier post of mine, but i thought I should make it a separate thread, since it's not really the same topic
I'd like the commands
syms x lambda
f = @(x)B(x);
g = @(x)lambda*C(x);
h = @(x)f(x) - g(x);
diff(h,x)
to "go inside of h(x)" and differentiate both f and g, to return
diff(B(x), x) - lambda*diff(C(x), x)
Instead it returns
diff(f(x), x) - diff(g(x), x)
I get the answer I want if I use
syms x
f = sym('B(x)')
g = sym('lambda*C(x)')
h = f - g; diff(h,x)
but this coding is less flexible than the former, since the argument 'x' is "hard-coded" into my functions, so I would have to use subs everytime I want to give my functions different arguments.
So in short, what I'm hoping for is the best of both worlds, the flexibility provided by anonymous functions plus the recursive (and other) properties provided when I use "sym"
  댓글 수: 1
Oleg Komarov
Oleg Komarov 2012년 8월 13일
편집: Oleg Komarov 2012년 8월 13일
I don't see the problem, the subs() in a symbolic context it's just a line of code.

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답변 (1개)

Walter Roberson
Walter Roberson 2012년 8월 13일
diff() cannot be applied to function handles.

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