- You set options for fsolve, but then call lsqnonlin. This is a mistake.
- You do not pass options to the solver. This might be a mistake.
- You have six equations in four unknowns. Generally, you should not expect a solution to such a system, only a point that is a local minimum of the sum of squares.
How to solve 4 equations with 4 unknowns with bounds?
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Hi everyone, I'm trying to solve this but the message displayed local minimum found and also the values of the x generated did not match with the boundary which was set ie. x(1)+x(2) = Ym. It also says lsqnonlin stopped because the final change in the sum of squares relative to its initial value is less than the value of the function tolerance.Could anyone help with this? Many thanks!
clear; clc;
x0 = [50; 50; 50; 50;];
options = optimoptions('fsolve','Display','iter');
%[x,fval] = fsolve(@myfun,x0,options)
lb = [0; 0; 0; 0;];
ub = [100; 100; 100; 100;];
x = lsqnonlin(@myfun,x0,lb,ub)
myfun(x)
function F = myfun(x)
A = 87.3145;
B = -0.289762;
C = 0.0000199677;
alpha = 0.4705;
Xm = 20;
Ym = 27.5;
F = [x(1)+x(2)-Ym;
x(3)+x(4)-Xm;
A*exp(B*x(3)^0.5 - C*x(3)^3) - x(1);
A*exp(B*x(4)^0.5 - C*x(4)^3) - x(2);
Ym/alpha - ((1-alpha)/alpha)*x(2) - x(1);
Xm/alpha - ((1-alpha)/alpha)*x(4) - x(3);
]
end
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채택된 답변
Alan Weiss
2019년 4월 22일
Alan Weiss
MATLAB mathematical toolbox documentation
추가 답변 (1개)
Alex Sha
2019년 5월 16일
Refer the results below:
x1: 7.73410323214524
x2: 32.0801819920043
x3: 33.4573119565274
x4: 11.2688338748665
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