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how i can save the value of two signals when they are equal
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i want to save the value of these two signals when they have an equal value in each period
i wrote this code but it's not true
a = zeros(1,14);
if signal_1 == signal_2
a(b) = signal_1
b = b+1;
end
b=mod(b,14);
code needs to define the value of "b" and if i define that it cant continues to 14
댓글 수: 2
Raj
2019년 4월 19일
Your 'if' condition logic will not serve the purpose. Depending on the first value of the signals, either the execution will not enter this condition or will enter and exit with only one match. Do you have the equations/workspace variables for signal_1 and signal_2?
답변 (3개)
Walter Roberson
2019년 4월 19일
편집: Walter Roberson
2019년 4월 19일
N = 14;
a = zeros(1, N);
b = 1;
for K = 1 : length(signal_1)
if signal_1(K) == signal_2(K)
a(b) = signal_1(K);
b = mod(b, N) + 1;
end
end
I know that mod(b,N)+1 might look wrong, but it is correct. b = 1 is sent to 2, b = 2 is sent to 3, ... b = 13 is sent to 14, b = 14 then mod(b,14) is 0 and then you add 1 to that giving 1, so b = 14 is sent to 1.
댓글 수: 2
Walter Roberson
2019년 4월 19일
I have to guess about meaningful outputs of this.
function a_copy = fcn(signal_1, signal_2)
N = 14;
persistent a b
if isempty(a) || isempty(b)
a = zeros(1, N);
b = 1;
end
if signal_1 == signal_2
a(b) = signal_1;
b = mod(b,N) + 1;
end
a_copy = a;
esmaeil keyvanloo
2019년 4월 19일
댓글 수: 1
Walter Roberson
2019년 4월 19일
Perhaps you could use a global block to store a and b
Or make them signals that are given initial values and which feed back into the block. Just make sure that you have a unit delay block so you do not accidentally create an algebraic loop.
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