need help with fprintf

조회 수: 2 (최근 30일)
Jung
Jung 2019년 3월 26일
댓글: Walter Roberson 2019년 3월 27일
Hi all,
I have this line of script where it takes a parameter text file (par.txt) and changes the variables for calibration purpose.
fout=fopen('par.txt','w+')
fprintf(fout,'wcwp\t%6f\t%6f\t%6f\t%6f\t%6f\r\n', x(1),x(1),x(1),x(1),x(2));
Here, I'd like to implement this line so I can increase the values at a same rate as the other varialbes
fprintf(fout,'wcwp\t0.4*%6f\t0.4*%6f\t0.4*%6f\t0.4*%6f\t0.4*%6f\r\n', 0.4,0.4,0.4,0.4,0.8);
But, once I run this script, my output looks like this;
wcwp 0.4*0.400000 0.4*0.400000 0.4*0.400000 0.4*0.400000 0.4*0.800000
I need to find a way where I can have %6f value multiply by something and still show the final answer to the txt file
Any help would be appreciated

답변 (1개)

Walter Roberson
Walter Roberson 2019년 3월 26일
fprintf(fout,'wcwp\t%6f\t%6f\t%6f\t%6f\t%6f\r\n', 0.4*([x(1),x(1),x(1),x(1),x(2)]);
  댓글 수: 2
Jung
Jung 2019년 3월 27일
Thanks for the reply.
What if instead of fixed value, such as 0.4 in the example, I'd like a range of value for x(1)... so that whenever I calibrate the data, the rate/percentage of differences is constant for x(1) and x(2).
For instance, I would want my parameters to be calibrated within the 10% range so [0.9 to 1.2] so these values would be multiplied by variables
Walter Roberson
Walter Roberson 2019년 3월 27일
Change the 0.4 to a variable name of a variable you calculate just before this.

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