How do I evaluate the area between two curves?

I'm given:

y= and y=. It's interval x [0; inf)

How do I calculate the area of this figure?

[dpb]

So, what have you done and where did you get stuck?

What toolboxes are you allowed to use?

[nexwa]

I'm not sure what to do at the first place but I assume I have to write something like this? Also what do you mean with toolboxes? We are using simply script editor in matlab

syms x
fplot((3x^2-12.3x+6),[?]),axis equal, axis([?]), hold on
fplot((-x^3+3.22x^2-2x+2.94,[?]),plot([?],[?]),grid on
solve((3x^2-12.3x+6)==(-x^3+3.22x^2-2x+2.94),x)
S=int((3x^2-12.3x+6)-(-x^3+3.22x^2-2x+2.94),x,?,?) // I'm not sure what I should write instead of question marks in my problem.

Answer 1

[nexwa]

I've solved it, apparantly it was really easy haha, anyways, in case anyone would like to know here's the code:

clear all
clc
syms x
y1=3*x^2-12.3*x+6;
y2=-x^3+3.22*x^2-2*x+2.94;
vpa(solve(y1==y2),6)
fplot(3*x^2-12.3*x+6, [0 4]), hold on
fplot(-x^3+3.22*x^2-2*x+2.94, [0 4])
S=vpa(int((y2-y1),x,0.297757,3.16711),6)

[madhan ravi]

+1, you may also be interested in representing the array graphically as well.