Repalce zero element by the number before it ?

조회 수: 2 (최근 30일)
Willim
Willim 2019년 1월 17일
편집: madhan ravi 2019년 1월 17일
If I have array called N,
N = [2 0 7 0 9 10 0 0 11 0 0 ];
I want to create new array M that have [2 2 7 7 9 10 10 10 11 11 11]
Here is other example
N=[ 0 1 4 5 6 7 0 10 0 0 0]
the one I would create is
M=[0 1 4 5 6 7 7 10 10 10 10].
I would replace each zero in array N by the number before it except the first zero.
Thank you in advance.

채택된 답변

Image Analyst
Image Analyst 2019년 1월 17일
Faraj:
Did you try the super obvious solution: a very simple "for" loop:
N = [2 0 7 0 9 10 0 0 11 0 0 ];
for k = 1 : length(N)
if N(k) == 0
N(k) = N(k-1);
end
end
Presumably so. Were you looking for some more compact vectorized or function-based solution instead?

추가 답변 (2개)

KSSV
KSSV 2019년 1월 17일
N=[ 0 1 4 5 6 7 0 10 0 0 0] ;
M = N ;
idx = find(N==0) ; % get the indices of zeros
while ~isempty(idx)
idx(idx==1) = [] ; % remove the index if zero is at one
M(idx) = M(idx-1) ; % replace zeros with previous values
idx = find(M==0) ;
idx(idx==1) = [] ;
end
  댓글 수: 2
Willim
Willim 2019년 1월 17일
This works but for my entire code , my code keeps running until I pause the run and quit debugging. then type M in my command window then I got the right M.
could you please the algorithm code ?
KSSV
KSSV 2019년 1월 17일
Give the value of N. Image Analyist solution is good....go ahead with that.

댓글을 달려면 로그인하십시오.


madhan ravi
madhan ravi 2019년 1월 17일
편집: madhan ravi 2019년 1월 17일
EDITED
N = [2 0 7 0 9 10 0 0 11 0 0 ];
M=N;
M(M==0)=NaN;
M=fillmissing(M,'nearest')
Gives:
M =
2 2 7 7 9 10 10 10 11 11 11
N=[ 0 1 4 5 6 7 0 10 0 0 0];
M=N;
M(M==0)=NaN;
M=fillmissing(M,'previous');
M(1)=0
Gives:
M =
0 1 4 5 6 7 7 10 10 10 10
  댓글 수: 5
Willim
Willim 2019년 1월 17일
great it works but the thing is that the frist element could be 1 not 0 all the time
madhan ravi
madhan ravi 2019년 1월 17일
편집: madhan ravi 2019년 1월 17일
What? Did you see the first example in my answer?

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by