Operands to the || and && operators must be convertible to logical scalar values.

조회 수: 1 (최근 30일)
I have such kind of simple code. But when I tried to include it in "if else" like below, this command: Operands to the || and && operators must be convertible to logical scalar values, just appears.
prompt1 = {'sth 1:' , 'sth 2:' };
title = 'Front Range';
dims = [1 50] ;
definput = {' ', ' '};
x1 = inputdlg(prompt1,title,dims,definput);
if ge(x1, 100) || lt(x1, 1)
return
else
prompt2 = {'sth 3:' , 'sth 4:' };
title2 = 'Post-Range';
dims2 = [1 50];
definput2 = {' ',''};
x2 = inputdlg(prompt1,title2,dims2,definput2);
end
  댓글 수: 1
Rik
Rik 2018년 12월 23일
With the debugger enabled, you can try to evaluate the parts of that statement. Both parts should be a logical scalar. Apparently that is currently not the case.

댓글을 달려면 로그인하십시오.

채택된 답변

Walter Roberson
Walter Roberson 2018년 12월 23일
inputdlg() returns a cell array of character vectors. You need to use str2double(x1) to convert to numeric form. Watch out for nan, which will be returned for empty values or for values that are not valid single numbers.

추가 답변 (1개)

Image Analyst
Image Analyst 2018년 12월 24일
Try this:
ca = inputdlg(prompt1, 'Front Range', dims, definput);
% ca is a cell array.
sth1 = str2double(ca{1})
sth2 = str2double(ca{2})
if sth1 < 1 || sth1 > 100 || sth2 < 1 || sth2 > 100
return;
else........
Don't use title as the name of your variable because that is the name of a built-in function.

카테고리

Help CenterFile Exchange에서 MATLAB에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by