Could someone explain how this code works?

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IBM watson
IBM watson 2018년 10월 23일
댓글: Torsten 2018년 10월 24일
S=[1 3 0 2 0 0];
C=[0 2];
[~,col] = ismember(C,S);
S(col) = [];
S =
1 3 0 0
This code is for : exclude C from S with repetition while keeping the same order of elements in S.
But how it works?
[~,col] = ismember(C,S);

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Guillaume
Guillaume 2018년 10월 23일
편집: Guillaume 2018년 10월 23일
I'm not sure what there is to explain. As documented, col tells you where each element corresponding element of C is found in S. If the element of C is found in more than one position, you'll get the first one of these.
The code is also flawed and will error if any element of C is not found at all in S. The safe version of the code would be:
S = [1 3 0 2 0 0];
C = [0 2 4]; %note that the original code would error because 4 is not present is S
[found, where] = ismember(C, S);
S(where(found)) = [] %this will not error
  댓글 수: 4
IBM watson
IBM watson 2018년 10월 23일
Many thanks to you!
Torsten
Torsten 2018년 10월 24일
Note that the code from above assumes that the elements in C are distinct.
So setting
S=[1 3 0 2 0 0];
C=[0 0 2];
will not produce
S=[1 3 0]
but also
S=[1 3 0 0]
Best wishes
Torsten.

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