nearest tangent point from Ginput point to line ?
조회 수: 2 (최근 30일)
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I'm trying to get the nearest by creating a ginput and then ginput point finds the nearest point to the line.
x = [0,20]
y= [20,50]
plot(x,y)
[x,y] = ginput(1);
h1 = text(x,y,'o', ...
'HorizontalAlignment','center', ...
'Color', [1 0 0], ...
'FontSize',8);
채택된 답변
Rik
2018년 10월 22일
My FEX submission should help here. Unlike what the documented behavior should be, pt is actually not extended to 3D automatically, so you'll have to do that yourself until I update the file. The code below should work as intended.
x = [0,20];
y= [20,50];
v1=[x(1) y(1) 0];
v2=[x(2) y(2) 0];
plot(x,y)
[x,y] = ginput(1);
pt=[x(:),y(:),zeros(numel(y),1)];
h1 = text(x,y,'o', ...
'HorizontalAlignment','center', ...
'Color', [1 0 0], ...
'FontSize',8);
distance=point_to_line_distance(pt, v1, v2)
댓글 수: 11
Rik
2018년 10월 30일
Did this suggestion solve your problem? If so, please consider marking it as accepted answer. It will make it easier for other people with the same question to find an answer. If this didn't solve your question, please comment with what problems you are still having.
Image Analyst
2018년 10월 30일
Perhaps have your code draw a line from the point perpendicularly to the closest point on the line, then run your code, and save a screenshot of the figure and upload it. Maybe if he sees that he will accept it.
추가 답변 (1개)
Image Analyst
2018년 10월 22일
Use sqrt():
uiwait(helpdlg('Click one point.'));
[xUser, yUser] = ginput(1);
distances = sqrt((xUser - xLine).^2 + (yUser - yLine) .^ 2);
[minDistance, indexOfMin] = min(distances);
hold on;
% Put a marker on the line.
plot(xLine(indexOfMin), yLine(indexOfMin), 'r*');
% Draw a line from the user-clicked point to the point on the line.
line([xUser, xLine(indexOfMin)], [yUser, yLine(indexOfMin)], 'LineWIdth', 2, 'Color', 'r');
댓글 수: 3
Image Analyst
2018년 10월 23일
OK, I thought you had a bunch of points along a line, not just two. In that case you'll have to use the point-to-line distance formula, which are readily avalable all over the web.
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