How to count non-zero elements in a column but over a specified range?

I'm trying to get the sum of non-zero elements in a column and store these values. The column consists of a list of numbers that range from 1 to 5000 and then repeats again 1 to 5000. I'm trying to count the number of non-zero elements in one range (from 1 to 5000), store this value, and then move onto the next range of 1 to 5000, store this value etc.

I've tried the following:

store_sum = zeros(length(list_values));
for i = 1:length(list_values)
  for j = 0:5000
  store_sum = sum( i ~= 0,1);
  end
end

[Walter Roberson]

Are the cycles always 5000 apart -- the full 1:5000 but with some values replaced by 0? Or is it the case that you have a sorted subset of 1:5000 except that the sorted subset might have 0's in it?

Answer 1

[Matt J]

This may be what you want, but your description of the problem is very hard to interpret. You just want the number of non-zero elements in each column of true_spike?

store_sum = sum(true_spike>0)

[Matt J]

But all non-zero elements in the entire matrix are between 1 and 5000, so effectively, you are asking for the number of non-zero elements in the column. And what about the other columns?

[Image Analyst]

What is true_spike? He doesn't mention it, at least in the current form of his question.

I can't figure out what "repeats" means. Let's say that column has 100 elements with values in the range 0-5000. But then what does repeat mean? Like rows 101 to 200 or whatever also are in the range 0 to 5000? How are we supposed to know where these ranges start and stop? You just took the sum over the whole column, which is what I would have done, given the lack of information. I guess it was correct because he accepted it.