How can I display high precision number in engineering format?

조회 수: 6 (최근 30일)
Sree Ranjini
Sree Ranjini 2016년 10월 14일
편집: Walter Roberson 2016년 10월 16일
I need to display my results in engineering format with large exponential values( for eg. 3.14159e-070). 'format longE' doesn't helps in this case. I used vpa function but it displays the result in expanded format (for eg. 0.000000000000000000000000000000000000000000000000000000000000000000000000003141592653589793299). How can I display my results in exponential form with high negative powers? Thanks in advance.

답변 (1개)

Star Strider
Star Strider 2016년 10월 14일
I wrote a utility function for my own use that you may find useful:
engstr = @(x) [x*10.^(-3*floor(log10(abs(x))/3)) 3*floor(log10(abs(x))/3)];
Q1 = Your_Number_Here;
Result2 = sprintf('%.4fe%+04d', engstr(Q1))
The ‘engstr’ function calculates the mantissa and exponent as a (1x2) vector. The ‘Result2’ assignment demonstrates a way to print them.
  댓글 수: 3
Star Strider
Star Strider 2016년 10월 16일
My pleasure.
Use double instead of vpa, or change the ‘Result2’ assignment to:
Result2 = sprintf('%.4fe%+04d', engstr(double(Q1)))
That should work.
Walter Roberson
Walter Roberson 2016년 10월 16일
편집: Walter Roberson 2016년 10월 16일
It won't display the results in high precision with accuracy. The question is about reformatting a high precision symbolic number to still have high precision but engineering format. (I think. The text and the tags are not entirely clear about it.)

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