How to control output of a function ?

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Jacky Jo
Jacky Jo 2015년 10월 25일
편집: Jacky Jo 2015년 10월 25일
I have written a function for spherical harmonics in which I want to control the ' Plotting area ' in such a way that, when we call the function into a variable, (i.e, lets say variable X= Plt( 10,30)*) I don't wanna show the plotting part. Otherwise (i.e, if the function _ Plt(10,30)* calling in a command window or somewhere in any other scripts, the plotting part of the function should run/ show the plots. The code has given below. (I have also attached the Plt.m* file with this.) Please give me an idea/ answer.... Thanks in advance.!
function [ P_bar ] = Plt( Degree_or_Order, Theta_In_Degree )
%%Content
%---------------------------------Plotting of Data--------------------------------
if grid_legth>1 % Works if ''theta'' is a grid of angles.
r=0;
for m=0:M
figure; width=1;
for L=r:L_max
PP=reshape(P_bar(L+1,m+1,1:grid_legth),1,grid_legth);
plot(T,PP,'linewidth',(1+(width/10)),'Color',rand(1,3));
hold on; grid on; width=width+1;
end
title(['Plote of P_(_:_,_' num2str(m) '_)']);
xlabel('Co-Latitude[Degree]');
[Lidx,Midx] = ndgrid(r:L_max,m);
legends = cellstr(num2str([Lidx(:),Midx(:)],'L = %d, M = %d'));
legend(legends,'Location','NorthEastOutside');
r=r+1;
end
figure;
PP=reshape(P_bar(L_max+1,M+1,1:grid_legth),1,grid_legth);
plot(T,PP,'linewidth',2); grid on;
xlabel('Co-Latitude[Degree]');
title(['Plote of P(' num2str(L_max) ',' num2str(M) ')']);
elseif grid_legth==1 % Works for a perticular co-latitude.
figure;
for m=0:M
a = linspace(10,150,L_max+1);
scatter(0:L_max,P_bar(:,m+1),a,'filled');
hold on; grid on;
end
[Midx] = ndgrid(0:M);
legends = cellstr(num2str([Midx(:)],' M = %d'));
legend(legends,'Location','NorthEastOutside');
title(['Scatter of P(' num2str(L_max) ',' num2str(m) ') with theta= ' num2str(T) ' degree']);
xlabel('Degree of Legendre Function (0 to L_m_a_x)');
end
end

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Walter Roberson
Walter Roberson 2015년 10월 25일
nargout is 0 if there is no assignment implied in the way it was called
  댓글 수: 1
Jacky Jo
Jacky Jo 2015년 10월 25일
Yes.... It's working... Thank you very much, Walter Roberson!

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