Calculate the sum of these two vectors using loops. Can't use sum()

Use loops to calculate the sum of two row vectors a & b, each of dimension 9. c(i)=a(i) + b(i) for i=1:9;

My current code looks like this:

clear;
a=zeros(1,9);
b=zeros(1,9);
c=zeros(1,9);
for i=1:9;
    c(i)= a(i)+ b(i);
end;
disp(c);

Answer 1

[Torsten]

Your code is ok although you just could have set

c=a+b;

I wonder why you are supposed to use a loop.

Best wishes

Torsten.

Answer 2

[Eric]

My output is just not right though.

output:

   0     0     0     0     0     0     0     0     0

[Ilham Hardy]

Why do you think this is incorrect?

[Eric]

isn't it suppose to work something like this:

      a               +          b        =        c
    1 1 1 1 1 1 1 1 1 + 1 1 1 1 1 1 1 1 1 = 2 2 2 2 2 2 2 2 2
    2 2 2 2 2 2 2 2 2 + 2 2 2 2 2 2 2 2 2 = 4 4 4 4 4 4 4 4 4
    3 3 3 3 3 3 3 3 3 + 3 3 3 3 3 3 3 3 3 = 6 6 6 6 6 6 6 6 6

etc etc up to 9

and then add up all the c's?

Or is my understanding of vectors wrong?

[nhagen]

It actually works like that, but in your original post you're basically doing 0+0=0...

[nhagen]

a=ones(1,9);
b=ones(1,9)*3;
c=zeros(1,9);
c=a+b;
disp(a);
disp(b);
disp(c);

[Torsten]

You have

a=[0 0 0 0 0 0 0 0 0]
b=[0 0 0 0 0 0 0 0 0]

What you do in the loop is to sum a and b componentwise, thus

c=[0+0 0+0 0+0 0+0 0+0 0+0 0+0 0+0 0+0]

and the result is

c=[0 0 0 0 0 0 0 0 0]

Best wishes

Torsten.

Answer 3

[Eric]

Ok, but I'm trying to replace the values of zero with 1,2,3...9, so how do I replace the loop to sum numbers 1:9

Sorry if my question wasn't clear enough.

[Torsten]

If you want to sum numbers 1,...,9:

summe=0;
for i=1:9
summe=summe+i;
end
disp(summe);

Best wishes

Torsten.

Answer 4

[Eric]

I attached the question to make things more clear

[Torsten]

If this is the question, your original code is correct.

Best wishes

Torsten.