How to interpolate a set of data wher the X size is different for the Y size

조회 수: 12 (최근 30일)
Hello,
I have a set of data X (size=2001,1) and Y (size=3,1). The Z matrix size is (2001,3). X and Y have uniform increments by the X size is not the same as the size of Y.
Can I use meshgrid or interp2? I tried but I got errors
for meshgrid
Error using griddata
The lengths of X and Y must match the size of Z.
for interp2
Error using griddedInterpolant
Sample points vector corresponding to grid dimension 1 must contain 3 elements.
Error in interp2>makegriddedinterp (line 226)
F = griddedInterpolant(varargin{:});
Error in interp2 (line 126)
F = makegriddedinterp({X, Y}, V, method,extrap);
Error in read_mydata (line 41)
Vq = interp2(theta,phi,co_amp_db,10,22);
Error in read_mydata (line 40)
vq = griddata(theta,phi,co_amp_db,10,22)
=======================================
Here is my code
xlx=input_data_file;
sheetname='MAIN';
addpath(pathToOptimizer)
nrow=2002;
ncol=13;
rangero=[1,1,nrow,ncol];
sheetname='Test';
[NUM,TXT,RAW]=readmycells(xlx,rangero,sheetname);
phi=NUM(1,3:4:ncol)';
theta=NUM(2:nrow,1);
nnp=size(phi);
nnt=size(theta);
np=nnp(2);
nt=nnt(1);
co_amp_db=NUM(2:nrow,2:4:ncol);
co_phase_db=NUM(2:nrow,3:4:ncol);
cx_amp_db=NUM(2:nrow,4:4:ncol);
cx_phase_db=NUM(2:nrow,5:4:ncol);
vq = griddata(theta,phi,co_amp_db,10,22);
Vq = interp2(theta,phi,co_amp_db,10,22);

채택된 답변

dpb
dpb 2023년 1월 21일
x=1:10;y=1:3; % coarse spacing
z=rand(numel(x),numel(y));
surf(y,x.',z)
hold on
Z=interp2(y,x.',z,1:0.5:3,[1:0.5:10].'); % increase spacing by half...
surf(1:0.5:3,[1:0.5:10].',Z); % plot on top...
  댓글 수: 4
VBBV
VBBV 2023년 1월 22일
이동: VBBV 2023년 1월 22일
Check also scatteredInterpolant or griddedInterpolant

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Jonas
Jonas 2023년 1월 21일
you can usw meshgrid to prepare your xq and yq:
Y=9:13;X=1:2:5;Z=rand(5,3);
[xq,yq]=meshgrid(1:0.5:5,9:0.5:13);
interp2(X,Y,Z,xq,yq)

카테고리

Help CenterFile Exchange에서 Interpolation에 대해 자세히 알아보기

제품


릴리스

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by