# I can't figure out why am not getting a plot on my code

조회 수: 1(최근 30일)
John 2022년 10월 25일
답변: Chunru 2022년 10월 25일
Write a MATLAB code for plot original and transformation function of
function y=ga(t);
y = -2*(t<=-1)+2*t.*(-1<t&t<=1)+(3-t.^2).*(1<t&t<=3)-6*(t>3);
figure;
tmin=-3;tmax=8;N=100;
dt=(tmax-tmin)/N; t=tmin+dt*[0:N]';
g0=ga(t);g1=-3*ga(4-t);
subplot(2,1,1);p=plot(t,g0,'k');set(p,'LineWidth',2);grid;
ylabel('g(t)');
title('(a)-g(t)=-2,t<-1,2t,-13')
subplot(2,1,2);p=plot(t,g1,'k');set(p,'LineWidth',2);grid;
xlabel('t');ylabel('-3g(4-t');

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### 답변(1개)

Chunru 2022년 10월 25일
If you put the script and local function ga in the same file, then local functions should be placed at the end of the files as shown below. You can also put the local function in a separate file,
figure;
tmin=-3;tmax=8;N=100;
dt=(tmax-tmin)/N; t=tmin+dt*[0:N]';
g0=ga(t);g1=-3*ga(4-t);
subplot(2,1,1);p=plot(t,g0,'k');set(p,'LineWidth',2);grid;
ylabel('g(t)');
title('(a)-g(t)=-2,t<-1,2t,-13')
subplot(2,1,2);p=plot(t,g1,'k');set(p,'LineWidth',2);grid;
xlabel('t');ylabel('-3g(4-t');
function y=ga(t);
y = -2*(t<=-1)+2*t.*(-1<t&t<=1)+(3-t.^2).*(1<t&t<=3)-6*(t>3);
end

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