Is there a more efficient way to format my vector rather than manually change the code

조회 수: 1 (최근 30일)
T = 5400;
INT = 900;
tme = 0:INT:T;
TV = [tme(1):30:tme(2)-30, tme(2):15:tme(3)-15, tme(3):12:tme(4)-12, tme(4):2.4:tme(5)-2.4, tme(5):2.1428:tme(6)-2.1428, tme(6):2.5:tme(7)-2.5];
I have this code, however is there an easier way to code this if i want to change the values for 'T' and 'INT' to any random value, for the' TV' vector to automatically update rather than me manually put tme(1), tme(2) etc for those respective values in the 'tme' vector
  댓글 수: 2
Bruno Luong
Bruno Luong 2022년 8월 16일
편집: Bruno Luong 2022년 8월 16일
Until you explain the law to obtain steps 30, 15, 12, 2.4, 2.1428, 2.5, then no you have to enter it by hand.
Adil Saeed
Adil Saeed 2022년 8월 16일
%Time
T = 5400;
INT = 900;
tme = 0:INT:T;
%Number of Positions and Impacts
Pn = 1320;
In = [30, 60, 75, 375, 420, 360];
TV = [tme(1):INT/In(1):tme(2)-INT/In(1), tme(2):INT/In(2):tme(3)-INT/In(2), tme(3):INT/In(3):tme(4)-INT/In(3), tme(4):INT/In(4):tme(5)-INT/In(4),...
tme(5):INT/In(5):tme(6)-INT/In(5), tme(6):INT/In(6):tme(7)-INT/In(6)];
I want to change 'T', 'INT' and 'In'. The number of values in 'In' should be equal to T/INT. So if we did change T = 5000; INT = 500; and the number of values in In = 10, these values can be random however summed should equal 'Pn', how can that 'TV' vector change automatically to cater this change or how can we combine these condition to produce the 'TV' vector

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채택된 답변

David Hill
David Hill 2022년 8월 16일
TV =@(tme) [tme(1):30:tme(2)-30, tme(2):15:tme(3)-15, tme(3):12:tme(4)-12,...
tme(4):2.4:tme(5)-2.4, tme(5):2.1428:tme(6)-2.1428, tme(6):2.5:tme(7)-2.5];
tv1=TV(0:900:5400);
tv2=TV(0:500:5000);
  댓글 수: 5
John D'Errico
John D'Errico 2022년 8월 16일
It IS (sort of) an answer to your question as posed. I (or anyone) might have been moved to answer a separate question, that was posed more accurately, OR an unaccepted and clarified question. You might even find that David then makes his answer a general solution then.

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