Store mxn matrix within a for loop
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How can I store results of a for loop when one iteration gives m x n matrix and not a 1 x n matrix?
a = rand(20,12);
for k=length(a)
store_this = reshape((a(k,:)), 3, [])';
end
**EDIT
The sample code I wanted to share is as follows, and the one above is wrong as pointed out :)
a = rand(20,12);
for k=1:size(a,1)
store_this = reshape((a(k,:)), 3, [])';
end
댓글 수: 2
Rik
2022년 7월 19일
Your loop is confusing.
Did you intend to have a single iteration?
Did you intend to use max(size(a))? Judging from your indexing, you may have wanted size(a,1) instead.
If you would have multiple iterations, that would mean your array gets overwritten every time. Is that intentional?
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Rik
2022년 7월 19일
편집: Rik
2022년 7월 19일
I'm not sure this is the optimal way to do it, but this does what you explain by using a cell array as an intermediary step.
a = rand(20,12);
store_this=cell(1,size(a,1));
for k=1:size(a,1)
store_this{k} = reshape((a(k,:)), 3, [])';
end
store_this=vertcat(store_this{:})
In this case your entire loop can be replaced by a single line:
x=reshape(a.',3,[]).';
isequal(x,store_this),store_this
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