I couldn't understand why this program is not working, is my all variable algorithm is correct?

조회 수: 2 (최근 30일)
clc
ti = 0;
tf = 10E-4;
tspan=[ti tf];
y0=[9;9;1;1;0].*10E-2;
I =0:0.1 :10 ;
Vf = zeros(length(I),1) ;
for i = 1:length(I)
[T,Y]= ode45(@(t,y) rate_eq(y,I(i)),tspan,y0);
Vf(i) = (2.*(((mean(Y(:,1).*Y(:,2).*cos(Y(:,5)))).^2 + (mean(Y(:,1).*Y(:,2).*sin(Y(:,5)))).^2).^0.5))/(mean(Y(:,1).^2)+mean(Y(:,2).^2));
end
disp(Vf)
NaN 0.3065 0.3449 0.3443 0.3617 0.3454 0.3619 0.3656 0.3589 0.3651 0.3622 0.3700 0.3750 0.3650 0.3792 0.3500 0.3687 0.3655 0.3635 0.3725 0.3723 0.3652 0.3573 0.3717 0.3687 0.3656 0.3690 0.3614 0.3664 0.3588 0.3699 0.3821 0.3566 0.3635 0.3592 0.3654 0.3608 0.3605 0.3619 0.3630 0.3488 0.3517 0.3569 0.3543 0.3494 0.3595 0.3527 0.3370 0.3590 0.3579 0.3559 0.3545 0.3431 0.3577 0.3573 0.3474 0.3441 0.3554 0.3269 0.3347 0.3372 0.3471 0.3389 0.3368 0.3298 0.3292 0.3219 0.3263 0.3443 0.3386 0.3260 0.3428 0.3151 0.3296 0.3156 0.3189 0.3200 0.3148 0.3134 0.3150 0.3299 0.3187 0.3071 0.3029 0.3232 0.3056 0.2895 0.2976 0.3067 0.2846 0.3003 0.2848 0.2940 0.2972 0.2976 0.3055 0.3036 0.2962 0.2932 0.2946 0.3023
function dy = rate_eq(y,I)
dy = zeros(5,1);
o = 2E5; %detuning frequency
tc = 30E-9; %photon cavity lifetime
tf = 230E-6; %fluorescence lifetime
a1 = 0.1; %roundtrip loass
a2 = 0.1;
P1 = 0.2; %pumpstrength
P2 = 0.2;
kc = 3E-3; %critical coupling strength
s = 0.17;
k = s.*kc;
%amplitude equation
dy(1) = ((y(3) - a1) * y(1) + k * y(2) * cos(y(5))) ./ tc;
dy(2) = ((y(4) - a2) * y(2) + k * y(1) * cos(y(5))) ./ tc;
%gain medium strength
dy(3) = (P1 - y(3) * (((abs(y(1)))^2 .*I) + 1)) / tf;
dy(4) = (P2 - y(4) * (((abs(y(2)))^2 .*I) + 1)) / tf;
%phase differential equation
dy(5) = o - (k / tc) * (((y(1) ./ y(2)) + (y(2) ./ y(1))) * sin(y(5)));
end
  댓글 수: 3

댓글을 달려면 로그인하십시오.

채택된 답변

KSSV
KSSV 2022년 7월 12일
You need to interchange the variables to the function rate_eq. Try this:
ti = 0;
tf = 10E-4;
tspan=[ti tf];
y0=[9;9;1;1;0].*10E-2;
[T,Y]= ode45(@(t,y) rate_eq(t,y),tspan,y0);
I =0:0.1 :10 ;
Vf = zeros(length(I),1) ;
for i = 1:length(I)
[T,Y]= ode45(@(t,y) rate_eq(I(i),y),tspan,y0);
Vf(i) = (2.*(((mean(Y(:,1).*Y(:,2).*cos(Y(:,5)))).^2 + (mean(Y(:,1).*Y(:,2).*sin(Y(:,5)))).^2).^0.5))/(mean(Y(:,1).^2)+mean(Y(:,2).^2));
end
disp(I)
function dy = rate_eq(I,y)
dy = zeros(5,1);
o = 2E5; %detuning frequency
tc = 30E-9; %photon cavity lifetime
tf = 230E-6; %fluorescence lifetime
a1 = 0.1; %roundtrip loass
a2 = 0.1;
P1 = 0.2; %pumpstrength
P2 = 0.2;
kc = 3E-3; %critical coupling strength
s = 0.17;
k = s.*kc;
%amplitude equation
dy(1) = ((y(3) - a1) * y(1) + k * y(2) * cos(y(5))) ./ tc;
dy(2) = ((y(4) - a2) * y(2) + k * y(1) * cos(y(5))) ./ tc;
%gain medium strength
dy(3) = (P1 - y(3) * (((abs(y(1)))^2 .*I) + 1)) / tf;
dy(4) = (P2 - y(4) * (((abs(y(2)))^2 .*I) + 1)) / tf;
%phase differential equation
dy(5) = o - (k / tc) * (((y(1) ./ y(2)) + (y(2) ./ y(1))) * sin(y(5)));
end
  댓글 수: 2
SAHIL SAHOO
SAHIL SAHOO 2022년 7월 12일
would you explain me, if I change my dy =zeros(5,1) to dy = zeros(4,1) still it's working, why so?
I have 5 coupled differential equation this shouldn't happen right?
KSSV
KSSV 2022년 7월 12일
Though you define,dy = zeros(4,1)...you are defining
dy(5) = o - (k / tc) * (((y(1) ./ y(2)) + (y(2) ./ y(1))) * sin(y(5)));
so your dy is 5x1.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Programming에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by