"Index in position 2 is invalid. Array indices must be positive integers or logical values" when performing a for loop

Hi guys,

As you will be able to tell I am relatively new to Matlab. I have created an array "xrange" with 1 row, 99 elements. It has values ranging from around -7 to 3.5. UI(,) is a matrix of zeroes, which I am trying to fill the first column of using the loop below (N is a pre specified integer), where alpha = 0.25. Everytime I try to do this, i get the error stated in the question title. Please could someone give me some advice on where I may be going wrong?

for j = 1:N-1

UI(j,0) = exp(-alpha*xrange(j))*max(exp(xrange(j)) - K,0);

end

for j=1:N-1
UI(j,0) = exp(-alpha*xrange(j))*max(exp(xrange(j))-K,0);
end

Index in position 2 is invalid. Array indices must be positive integers or logical values.

Any help would be hugely appreciated, Thanks

Answer 1

[DGM]

MATLAB uses 1-based indexing, so UI(j,0) isn't a valid index. You can just use 1 for the first column.

The loop isn't really necessary.

xrange = 10.5*rand(1,99)-7;
alpha = 0.25;
K = 1; % idk what this is
N = 10; % some integer <=100

% use a loop to assign column 1 one row at a time
for j = 1:N-1
    UI(j,1) = exp(-alpha*xrange(j)) * max(exp(xrange(j))-K,0);
end

% or assign the whole column at once
idx = 1:N-1;
UI2(:,1) = (exp(-alpha*xrange(idx)) .* max(exp(xrange(idx))-K,0));

% show that the results are the same
immse(UI,UI2)

ans = 0

Either way works