How to sort a vector based on the absolute difference of the sorted vector
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Example: a= [2,3,6,12,7,18,25,0,28,5]
b= [0,2,3,5,6,7,12,18,25,28]
absolutediffofb=[2,1,2,1,1,5,6,7,3]
arrangeb=[(2,3)(5,6)(6,7)(0,2)(3,5)(25,28)(7,12)(12,18)(18,25)]
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Awais Saeed
2021년 12월 14일
It is not clear what you are trying to do? How do you read 'arrangeb'? Show us what have you tried and what issues are you facing.
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David Goodmanson
2021년 12월 14일
Hi Awais,
a= [2,3,6,12,7,18,25,0,28,5]
b = sort(a)' % column vector
c = [b(1:end-1) b(2:end)];
d = [diff(c,[],2) c];
e = sortrows(d)
e =
1 2 3
1 5 6
1 6 7
2 0 2
2 3 5
3 25 28
5 7 12
6 12 18
7 18 25
The ordered pairs are in columns 2 and 3. Some format like this is necessary since
[(2,3)(5,6)(6,7)(0,2)(3,5)(25,28)(7,12)(12,18)(18,25)]
is not part of Matlab syntax.
댓글 수: 3
Image Analyst
2021년 12월 15일
Where is "arrangeb"? It looks like you might be missing this:
arrangeb = e(:, 2:3);
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