In this code I have a result but I want it as integer numbers.
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n = 12;
m = 6;
numbers = linspace(1, n, m)
index = 1;
theSums = [];
for k = 1 : length(numbers)
for k2 = 1 : length(numbers)
num1(index) = numbers(k);
num2(index) = numbers(k2);
theSums(index) = num1(index) + num2(index);
fprintf('%.4f + %.4f = %.4f\n', num1(index), num2(index), theSums(index));
index = index + 1;
end
end
[uniqueSums, indexes] = unique(theSums)
% Extract only the unique numbers:
num1 = num1(indexes)
num2 = num2(indexes)
% Double check.
for k = 1 : length(indexes)
fprintf('%.4f + %.4f = %.4f\n', num1(k), num2(k), uniqueSums(k));
end
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답변 (1개)
Image Analyst
2021년 9월 26일
round() will turn floating point numbers (doubles) with fractions into floating point numbers (doubles) with no fraction (the fraction is 0).
Or you can use int32() to cast your variable into a 32 bit integer, which of course also does the rounding.
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