How to get correct p-values for the Steel-Dwass test?

조회 수: 10 (최근 30일)
T
T 2021년 9월 14일
댓글: T 2021년 9월 17일
I would like to create a code file for the Steel-Dwass test. I use a following smaple data with R (from: https://www.trifields.jp/introducing-steel-dwass-in-r-1632).
----------------------------------------------------------------------------------------------------------------------
> data <- c(
6.9, 7.5, 8.5, 8.4, 8.1, 8.7, 8.9, 8.2, 7.8, 7.3, 6.8,
9.6, 9.4, 9.5, 8.5, 9.4, 9.9, 8.7, 8.1, 7.8, 8.8,
5.7, 6.4, 6.8, 7.8, 7.6, 7.0, 7.7, 7.5, 6.8, 5.9,
7.6, 8.7, 8.5, 8.5, 9.0, 9.2, 9.3, 8.0, 7.2, 7.9, 7.8
)
> group <- rep(1:4, c(11, 10, 10, 11))
> Steel.Dwass(data, group)
t p
1:2 2.680234 0.036960431
1:3 2.539997 0.053980573
1:4 1.282642 0.574011771
2:3 3.746076 0.001031145
2:4 2.046776 0.170965537
3:4 3.384456 0.003976894
----------------------------------------------------------------------------------------------------------------------
I got the same t-values as bottom, but I could not get the same p-value. Could you help me?
Here is my code:
----------------------------------------------------------------------------------------------------------------------
data = [6.9 9.6 5.7 7.6; 7.5, 9.4, 6.4, 8.7; 8.5, 9.5, 6.8, 8.5; 8.4, 8.5, 7.8, 8.5; 8.1, 9.4, 7.6, 9; 8.7, 9.9, 7, 9.2; 8.9, 8.7, 7.7, 9.3;...
8.2, 8.1, 7.5, 8; 7.8, 7.8, 6.8, 7.2; 7.3, 8.8, 5.9, 7.9; 6.8, NaN, NaN, 7.8];
groupNum = size(data, 2);
N = zeros(groupNum, 1);
for i = 1:groupNum
N(i, 1) = length(data(:, i)) - sum(isnan(data(:, i)));
end
clear i
c = nchoosek(1:groupNum, 2);
t_steelDwass = zeros(length(c), 1);
p_steelDwass = zeros(length(c), 1);
stats_steelDwass = [];
for i = 1:length(c)
d1 = data(:, c(i, 1)); % group1 data
d2 = data(:, c(i, 2)); % group2 data
n1 = N(c(i, 1), 1); % group1 num
n2 = N(c(i, 2), 1); % group2 num
R = tiedrank([d1; d2]);
R2 = R.^2;
R2_sum = [sum(R2(1:length(d1), 1), 'omitnan'); sum(R2(length(d1)+1:length(R2), 1), 'omitnan')];
E = n1 * (n1 + n2 + 1) / 2;
x = (n1*n2) / ((n1 + n2)^2 - (n1 + n2));
y = sum(R2_sum) - (((n1 + n2) * (n1 + n2 + 1)^2)/4);
V = x * y;
t_steelDwass(i, 1) = abs((sum(R(1:length(d1), 1), 'omitnan') - E) / sqrt(V)); %%%%%%%%% t-value %%%%%%%%%
p_steelDwass(i, 1) = 1 - tcdf(t_steelDwass(i, 1), Inf); %%%%%%%%% p-value %%%%%%%%%
clear d1 d2 n1 n2 R R2 R2_sum E x y V
end
clear i
stats_steelDwass.df = groupNum;
stats_steelDwass.p = p_steelDwass;
stats_steelDwass.t = t_steelDwass;
stats_steelDwass.c = c;
clear p_steelDwass t_steelDwass c
stats_steelDwass.t
ans = 6×1
2.6802 2.5400 1.2826 3.7461 2.0468 3.3845
stats_steelDwass.p
ans = 6×1
0.0276 0.0320 0.1344 0.0100 0.0550 0.0138

답변 (1개)

Jeff Miller
Jeff Miller 2021년 9월 15일
The problem is with the 'inf' value given as the degrees of freedom in this line
p_steelDwass(i, 1) = 1 - tcdf(t_steelDwass(i, 1), Inf); %%%%%%%%% p-value %%%%%%%%%
I'm not familiar with the steel-dwass test, but I am pretty sure the df value should be n1+n2-2 (or something close to that) instead of Inf. If n1+n2-2 doesn't give you the right p values, you should be able to work out the correct df formula by changing that quantity (e.g., maybe n1+n2-1 or -3).
  댓글 수: 3
Jeff Miller
Jeff Miller 2021년 9월 16일
OK, then this function on file exchange is probably what you want: cdfTukey
T
T 2021년 9월 17일
The Tukey's HSD and the Steel-Dwass test are different. I could not get the correct p-value with the function.

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