how to get the row and column number of a specific value in an array

D:

42 24 20 17 20 24 19 18 18 15

39 21 19 17 20 18 18 19 15 18

32 20 14 13 17 16 15 15 14 16

27 19 11 12 12 20 14 13 17 18

26 14 10 11 13 16 11 12 16 17

24 10 14 16 19 9 12 17 18 21

e=[];
e(1)=min([D(1,end-1),D(2,end-1),D(2,end)]);

The end operator must be used within an array index expression.

how do i get the row and column number of e(1) in D

Answer 1

[Mathieu NOE]

hello

my suggestion :

it gives row = 2 and col = 9 (e = 15)

D = [42    24    20    17    20    24    19    18    18    15;
     39    21    19    17    20    18    18    19    15    18;
     32    20    14    13    17    16    15    15    14    16;
     27    19    11    12    12    20    14    13    17    18;
     26    14    10    11    13    16    11    12    16    17;
     24    10    14    16    19     9    12    17    18    21;];
 
 [m,n] = size(D);
 
 ind_x = [1 2 2];
 ind_y = [n-1 n-1 n];

e=[];
[e(1),ind] = min([D(ind_x(1),ind_y(1)),D(ind_x(2),ind_y(2)),D(ind_x(3),ind_y(3))]);  % [M,I] = min(X,[],...,'linear') returns the linear indices of the minimum values in vector I.
% results : 
row = ind_x(ind);
col = ind_y(ind);

[jeffery lamar]

it worked, thank you sir

[Mathieu NOE]

My pleasure

Answer 2

[Kevin Holly]

D=[
     42    24    20    17    20    24    19    18    18    15
     39    21    19    17    20    18    18    19    15    18
     32    20    14    13    17    16    15    15    14    16
     27    19    11    12    12    20    14    13    17    18
     26    14    10    11    13    16    11    12    16    17
     24    10    14    16    19     9    12    17    18    21];
 
 e=[];
[e(1) index]=min([D(1,end-1),D(2,end-1),D(2,end)]);

if index == 1
    row = 1;
    column = length(D(1,:))-1;
end
if index == 2
    row = 2;
    column = length(D(2,:))-1;
end
if index == 3
    row = 2;
    column = length(D(2,:));
end
row

row = 2

column

column = 9