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How can I get the sums of all possible combinations of the values of a vector?

조회 수: 1(최근 30일)
Tom de van der Schueren
Tom de van der Schueren 2021년 8월 19일
편집: Adam Danz 2021년 8월 19일
Dear all,
I would like to get the sums of all unique possible combinations of the values of a vector.
For example:
Input:
A = [10 20 30]
Output:
B = [10 20 30 (10+20) (10+30) (20+30) (10+20+30)]
If possible, I would also like to get the indices of the values used to get the sum, so:
C = [1 2 3 (1,2) (1,3) (2,3) (1,2,3)]
The output does not necessarily have to be a vector.
The length of the input vector (A) will vary from iterations to iterations, so I'm looking for a way to calculate B and C based on a changing vector A
All help would be greatly appreciated!
  댓글 수: 3
Adam Danz
Adam Danz 2021년 8월 19일
Agreed, the cell array is the way to go. Simple indexing,
b(i)
c{i}
However, there could be multiple solutions to the problem you described. For example, a vector [1 2 3 4] will result in two values of 3 (3, 1+2), two values of 4 (4, 1+3), two values of five, two values of 6, and two values of 7. So if you're trying to find the closest value in b to some target value, there may be a problem.

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Adam Danz
Adam Danz 2021년 8월 19일
% Input: v, a row or column vector
v = [2 4 6 8];
% create permutations and summation results
n = numel(v);
vIdx = 1:n;
results = cell(n,2);
for i = 1:n
results{i,1} = num2cell(nchoosek(vIdx,i),2)';
results{i,2} = sum(nchoosek(v,i),2)';
end
% Results
% b: 1xm row vector of summation results
% c: 1xm cell array of indicies of v for each summation
b = [results{:,2}]
b = 1×15
2 4 6 8 6 8 10 10 12 14 12 14 16 18 20
c = horzcat(results{:,1})
c = 1×15 cell array
{[1]} {[2]} {[3]} {[4]} {[1 2]} {[1 3]} {[1 4]} {[2 3]} {[2 4]} {[3 4]} {[1 2 3]} {[1 2 4]} {[1 3 4]} {[2 3 4]} {[1 2 3 4]}

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