What determines the shape of a logically indexed array?

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Ondrej Budac
Ondrej Budac 2014년 4월 3일
답변: Ondrej Budac 2014년 4월 7일
Matlab help explains: " Logical Indexing : ... The output is always in the form of a column vector."
In practice, typing
a = ones(3,3);
b = a([true, true]);
gives a row vector b. Can someone tell me why does it behave this way? And is there any other instance (apart from indexing by one row logical vector) that gives a non-column result? Thanks, O.

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Ondrej Budac
Ondrej Budac 2014년 4월 7일
Just to complete the story, the answer seems to be:
If B is a logical array and A is any array, then A(B) is equivalent (but faster) way to produce the same result as A(find(B)), including the shape of the output.

추가 답변 (1개)

Azzi Abdelmalek
Azzi Abdelmalek 2014년 4월 3일
Maybe you need
a = ones(3,3);
b = a([true, true],:)
  댓글 수: 7
Azzi Abdelmalek
Azzi Abdelmalek 2014년 4월 3일
Just one question, what are you expecting with a(logical([1 0;1 1])) ? The result contains 3 elements
Ondrej Budac
Ondrej Budac 2014년 4월 3일
If I now understand logical indexing correctly, I expect a(logical([1 0;1 1])) to give a column vector with values 1, 4, 2, assuming your definition of a.

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