swap columns of a matrix
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Hello guys/girls
How do i swap columns??
I have this
k_minus =
-46 -43 -26 -14 7 19 11 32 39 45 45
0 -4 -7 -7 -44 -44 -7 -7 -15 -15 0
and I want the columns to be in opposite order - How do I do this? and can do this in one go?
댓글 수: 1
Keerthi Krishna PARVATHANENI
2021년 9월 15일
Easy way is to swap the coloums based on the positon
For example:
A=[10 20 30;
40 50 60];
swap the coloum 1 to 2 can be done by
A(:,[2 1 3])
ans =
20 10 30
50 40 60
Exact approach can be adopted ot swap rows
A([2 1],:)
ans =
40 50 60
10 20 30
I think, this can be easy way with minium code.
Enjoy :)
추가 답변 (2개)
Mischa Kim
2014년 2월 25일
편집: Mischa Kim
2014년 2월 25일
Use
k_minus_rev = k_minus(:, [length(k_minus(1,:)):-1:1])
댓글 수: 4
Jos (10584)
2014년 2월 25일
You do not need the length statement by using the keyword END:
MyMatrix_withReversedColumns = MyMatrix(:,end:-1:1)
but I do suggest you stick to FLIPLR. It is the same, but much easier to read!
kk
2019년 4월 2일
Thank you for this answer! It has helped me "merge" two matrices, i.e. creating a matrix consisting of the first column of matrix A, first column of matrix B, second column of matrix A, second column of matrix B, etc.
rishabh gupta
2018년 1월 12일
you can also use: k_minus_rev = k_minus(:, [length(k_minus):-1:1])
댓글 수: 2
Stephen23
2018년 1월 12일
편집: Stephen23
2018년 1월 12일
The square brackets are totally superfluous, and using end is simpler than using length (of course length should be avoided generally because its output changes depending on the input array size: better to use numel or size with a specific dimension).
So a better (simpler, clearer, less buggy) is exactly as Jos already gave four years ago:
k_minus(:,end:-1:1)
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