# Normalized Perceptron Rule

A 2-input hard limit neuron is trained to classify 5 input vectors into two categories. Despite the fact that one input vector is much bigger than the others, training with LEARNPN is quick.

Each of the five column vectors in X defines a 2-element input vectors, and a row vector T defines the vector's target categories. Plot these vectors with PLOTPV.

```
X = [ -0.5 -0.5 +0.3 -0.1 -40; ...
-0.5 +0.5 -0.5 +1.0 50];
T = [1 1 0 0 1];
plotpv(X,T);
```

Note that 4 input vectors have much smaller magnitudes than the fifth vector in the upper left of the plot. The perceptron must properly classify the 5 input vectors in X into the two categories defined by T.

PERCEPTRON creates a new network with LEARPN learning rule, which is less sensative to large variations in input vector size than LEARNP (the default).

The network is then configured with the input and target data which results in initial values for its weights and bias. (Configuration is normally not necessary, as it is done automatically by ADAPT and TRAIN.)

net = perceptron('hardlim','learnpn'); net = configure(net,X,T);

Add the neuron's initial attempt at classification to the plot.

The initial weights are set to zero, so any input gives the same output and the classification line does not even appear on the plot. Fear not... we are going to train it!

```
hold on
linehandle = plotpc(net.IW{1},net.b{1});
```

ADAPT returns a new network object that performs as a better classifier, the network output, and the error. This loop allows the network to adapt, plots the classification line, and continues until the error is zero.

E = 1; while (sse(E)) [net,Y,E] = adapt(net,X,T); linehandle = plotpc(net.IW{1},net.b{1},linehandle); drawnow; end

Note that training with LEARNP took only 3 epochs, while solving the same problem with LEARNPN required 32 epochs. Thus, LEARNPN does much better job than LEARNP when there are large variations in input vector size.

Now SIM can be used to classify any other input vector. For example, classify an input vector of [0.7; 1.2].

A plot of this new point with the original training set shows how the network performs. To distinguish it from the training set, color it red.

x = [0.7; 1.2]; y = net(x); plotpv(x,y); circle = findobj(gca,'type','line'); circle.Color = 'red';

Turn on "hold" so the previous plot is not erased. Add the training set and the classification line to the plot.

hold on; plotpv(X,T); plotpc(net.IW{1},net.b{1}); hold off;

Finally, zoom into the area of interest.

The perceptron correctly classified our new point (in red) as category "zero" (represented by a circle) and not a "one" (represented by a plus). The perceptron learns properly in much shorter time in spite of the outlier (compare with the "Outlier Input Vectors" example).

axis([-2 2 -2 2]);

*Copyright 1992-2014 The MathWorks, Inc.*